【easy】Fizz Buzz-简单字符串输出

Problem 5：

Given number n. Print number from 1 to n. But:

• when number is divided by 3, print "fizz".
• when number is divided by 5, print "buzz".
• when number is divided by both 3 and 5, print "fizz buzz".

Example

If n = 15, you should return:

[
  "1", "2", "fizz",
  "4", "buzz", "fizz",
  "7", "8", "fizz",
  "buzz", "11", "fizz",
  "13", "14", "fizz buzz"
]

注意点：

1、for 循环的index 和 vector 中的值 的对应关系要找好，若不是3或5的倍数，vector[index]应为index+1;

2、最后返回的是vector<string>类型的向量，要用to_string()函数将int 转为 string；

代码：

class Solution {
public:
    /*
     * @param n: An integer
     * @return: A list of strings.
     */
    vector<string> fizzBuzz(int n) {
        // write your code here
         vector<string> a(n);
        if(n>0){
        for(int i = 0 ; i< n ; i++){
            int x = (i+1)%3;int y = (i+1)%5;
            if(x == 0 && y == 0){
                a[i] = "fizz buzz";
            }
            else if(x == 0){
                a[i] = "fizz";
            }
            else if(y == 0){
                a[i] = "buzz";
            }
            else
            {
                a[i] = to_string(i+1);
            }
        }
    }
    return a;
    }
};

发现把if(n>0)去了也是AC，因为要获得长度为n的数组，默认来说n是>=1的