LeetCode - Easy - 349. Intersection of Two Arrays

Topic

  • Hash Table
  • Two Pointers
  • Binary Search
  • Sort

Description

https://leetcode.com/problems/intersection-of-two-arrays/

Given two arrays, write a function to compute their intersection.

Example 1:

Input: nums1 = [1,2,2,1], nums2 = [2,2]
Output: [2]

Example 2:

Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
Output: [9,4]

Note:

  • Each element in the result must be unique.
  • The result can be in any order.

Analysis

方法一:我写的,使用Java8的特性

方法二:set的retainAll方法

方法三:传统做法

方法四:使用Java8的特性,比方法一更精简

方法五:位图法

还有其他方法,如,将实参的两数组分别排序,然后用双指针,或二分查找寻找出共同元素。

Submission

import java.util.Arrays;
import java.util.HashSet;
import java.util.Set;
import java.util.stream.Collectors;

public class IntersectionOfTwoArrays {
    
    

	// 方法一:我写的,使用 java8的特性
	public int[] intersection1(int[] nums1, int[] nums2) {
    
    
		Set<Integer> set1 = Arrays.stream(nums1).boxed().collect(Collectors.toSet());

		Set<Integer> tmp = new HashSet<>();
		for (int x : nums2)
			if (set1.contains(x))
				tmp.add(x);

		return tmp.stream().mapToInt(Integer::intValue).toArray();
	}

	// 方法二:set的retainAll方法
	public int[] intersection2(int[] nums1, int[] nums2) {
    
    
		Set<Integer> set1 = Arrays.stream(nums1).boxed().collect(Collectors.toSet());
		Set<Integer> set2 = Arrays.stream(nums2).boxed().collect(Collectors.toSet());
		set1.retainAll(set2);
		return set1.stream().mapToInt(Integer::intValue).toArray();
	}

	// 方法三:传统做法
	public int[] intersection3(int[] nums1, int[] nums2) {
    
    
		Set<Integer> set = new HashSet<>();
		Set<Integer> intersect = new HashSet<>();
		for (int i = 0; i < nums1.length; i++) {
    
    
			set.add(nums1[i]);
		}
		for (int i = 0; i < nums2.length; i++) {
    
    
			if (set.contains(nums2[i])) {
    
    
				intersect.add(nums2[i]);
			}
		}
		int[] result = new int[intersect.size()];
		int i = 0;
		for (Integer num : intersect) {
    
    
			result[i++] = num;
		}
		return result;
	}

	// 方法四:使用Java8的精简版
	public int[] intersection4(int[] nums1, int[] nums2) {
    
    
		Set<Integer> set = Arrays.stream(nums2).boxed().collect(Collectors.toSet());
		return Arrays.stream(nums1).distinct().filter(e -> set.contains(e)).toArray();
	}

	// 方法五:位图法
	public int[] intersection5(int[] nums1, int[] nums2) {
    
    
		int max = Integer.MIN_VALUE, min = Integer.MAX_VALUE;
		int[] ans = new int[nums1.length];
		int idx = 0;
		for (int i : nums1) {
    
    
			if (i > max)
				max = i;
			if (i < min)
				min = i;
		}
		for (int i : nums2) {
    
    
			if (i > max)
				max = i;
			if (i < min)
				min = i;
		}
		boolean[] map = new boolean[max - min + 1];
		for (int i : nums1)
			map[i - min] = true;
		for (int i : nums2) {
    
    
			if (map[i - min]) {
    
    
				ans[idx++] = i;
				map[i - min] = false;
			}
		}
		return Arrays.copyOf(ans, idx);
	}

}

Test

import static org.junit.Assert.*;

import java.util.Arrays;

import org.junit.Test;

public class IntersectionOfTwoArraysTest {
    
    

	@Test
	public void test1() {
    
    
		IntersectionOfTwoArrays obj = new IntersectionOfTwoArrays();
		assertArrayEquals(new int[] {
    
     2 }, //
				obj.intersection1(new int[] {
    
     1, 2, 2, 1 }, new int[] {
    
     2, 2 }));

		int[] expected = {
    
     9, 4 };
		int[] actual = obj.intersection1(new int[] {
    
     4, 9, 5 }, new int[] {
    
     9, 4, 9, 8, 4 });
		Arrays.sort(expected);
		Arrays.sort(actual);
		assertArrayEquals(expected, actual);
	}

	@Test
	public void test2() {
    
    
		IntersectionOfTwoArrays obj = new IntersectionOfTwoArrays();
		assertArrayEquals(new int[] {
    
     2 }, // 
				obj.intersection2(new int[] {
    
     1, 2, 2, 1 }, new int[] {
    
     2, 2 }));

		int[] expected = {
    
     9, 4 };
		int[] actual = obj.intersection2(new int[] {
    
     4, 9, 5 }, new int[] {
    
     9, 4, 9, 8, 4 });
		Arrays.sort(expected);
		Arrays.sort(actual);
		assertArrayEquals(expected, actual);
	}

	@Test
	public void test3() {
    
    
		IntersectionOfTwoArrays obj = new IntersectionOfTwoArrays();
		assertArrayEquals(new int[] {
    
     2 }, //
				obj.intersection3(new int[] {
    
     1, 2, 2, 1 }, new int[] {
    
     2, 2 }));

		int[] expected = {
    
     9, 4 };
		int[] actual = obj.intersection3(new int[] {
    
     4, 9, 5 }, new int[] {
    
     9, 4, 9, 8, 4 });
		Arrays.sort(expected);
		Arrays.sort(actual);
		assertArrayEquals(expected, actual);
	}

	@Test
	public void test4() {
    
    
		IntersectionOfTwoArrays obj = new IntersectionOfTwoArrays();
		assertArrayEquals(new int[] {
    
     2 }, //
				obj.intersection4(new int[] {
    
     1, 2, 2, 1 }, new int[] {
    
     2, 2 }));

		int[] expected = {
    
     9, 4 };
		int[] actual = obj.intersection4(new int[] {
    
     4, 9, 5 }, new int[] {
    
     9, 4, 9, 8, 4 });
		Arrays.sort(expected);
		Arrays.sort(actual);
		assertArrayEquals(expected, actual);
	}

	@Test
	public void test5() {
    
    
		IntersectionOfTwoArrays obj = new IntersectionOfTwoArrays();
		assertArrayEquals(new int[] {
    
     2 }, //
				obj.intersection5(new int[] {
    
     1, 2, 2, 1 }, new int[] {
    
     2, 2 }));

		int[] expected = {
    
     9, 4 };
		int[] actual = obj.intersection5(new int[] {
    
     4, 9, 5 }, new int[] {
    
     9, 4, 9, 8, 4 });
		Arrays.sort(expected);
		Arrays.sort(actual);
		assertArrayEquals(expected, actual);
	}
}

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转载自blog.csdn.net/u011863024/article/details/112270481