《Leetcode of December》118.杨辉三角

class Solution:
    def generate(self, numRows: int) -> List[List[int]]:
        
        #官方解法
        res = []
        for i in range(numRows):
            tmp = []
            for j in range(i+1):
                if j==0 or j==i:
                    tmp.append(1)
                else:
                    tmp.append(res[i-1][j-1]+res[i-1][j])
            res.append(tmp)
        
        return res


        #Mine
        if numRows==0:
            return []
        if numRows==1:
            return [[1]]
        if numRows==2:
            return [[1],[1,1]]
        
        res=[[1],[1,1]]
        for _ in range(2,numRows):
            tmp = [1,1]
            for i in range(len(res[-1])-1):
                num = res[-1][i]+res[-1][i+1]
                tmp.insert(i+1,num)
            res.append(tmp)
        return res

 总结:杨辉三角,找规律就行。num = res[-1][i]+res[-1][i+1]

 

猜你喜欢

转载自blog.csdn.net/weixin_37724529/article/details/110820566
今日推荐