【题解】CF631C：Report

原题传送门
如果我先做了一个 $[l,r]$的操作，又做了一个 $[l,r+1]$的操作，那么一开始的那个操作就没用了
可以记录每个点最晚的操作，从后往前逐位确定即可

Code：

#include <bits/stdc++.h>
#define maxn 200010
using namespace std;
int n, m, a[maxn], pos[maxn], type[maxn], Max, ans[maxn];

inline int read(){
	int s = 0, w = 1;
	char c = getchar();
	for (; !isdigit(c); c = getchar()) if (c == '-') w = -1;
	for (; isdigit(c); c = getchar()) s = (s << 1) + (s << 3) + (c ^ 48);
	return s * w;
}

int main(){
	n = read(), m = read();
	for (int i = 1; i <= n; ++i) a[i] = read();
	for (int i = 1; i <= m; ++i){
		int t = read(), r = read();
		pos[r] = i, type[r] = t;
		Max = max(Max, r);
	}
	sort(a + 1, a + 1 + Max);
	for (int i = n; i > Max; --i) ans[i] = a[i];
	int h = 1, t = Max, now = 0, opt = 0;
	for (int i = Max; i; --i){
		if (pos[i] > now) now = pos[i], opt = type[i];
		ans[i] = opt == 1 ? a[t--] : a[h++];
	}
	for (int i = 1; i <= n; ++i) printf("%d ", ans[i]);
	return 0;
}