判断是否为字符串重排（力扣）

import java.util.Arrays;

public class Test2 {
    public static void main(String[] args) {
        String s1 = "abc";
        String s2 = "cba";
        String s3 = "bcd";
        System.out.println(CheckPermutation(s1,s2));
        System.out.println(CheckPermutation2(s1,s3));
    }

    //字符串长度相等且互相包含
    public static boolean CheckPermutation(String s1, String s2) {
        if (s1.length() != s2.length()){
            return false;
        }
        for (int i = 0; i < s1.length(); i++) {
            if (!s2.contains(String.valueOf(s1.charAt(i)))){
                return false;
            }
        }
        for (int i = 0; i < s2.length(); i++) {
            if (!s1.contains(String.valueOf(s2.charAt(i)))){
                return false;
            }
        }
        return true;
    }

    //转字符数组排序再比较是否相等
    public static boolean CheckPermutation2(String s1, String s2) {
        char[] c1 = s1.toCharArray();
        Arrays.sort(c1);
        char[] c2 = s2.toCharArray();
        Arrays.sort(c2);
        return c1.equals(c2);
    }
}