2020-05-22 — 习题训练二-E

E - Candies and Two Sisters

题意：给定n,输出满足a+b=n,a>b的个数

解题思路：当n<=2时为0；n>2时，n是偶数为n/2-1,n是奇数为n/2.

ac代码：

#include<iostream>
using namespace std; int main(){ int t,n; cin>>t; while(t--){ cin>>n; if(n<=2){ cout<<"0"<<endl; } else{ if(n%2==0) cout<<n/2-1<<endl; else cout<<n/2<<endl; } } return 0; }