Jay:
Estoy tratando de leer un archivo de AWS S3 cubo y configurarlo como recurso dentro de mi primavera clase lector de lotes. Cuando la prueba de la aplicación en función de AWS lambda llegué a continuación error. cualquier experto sugerencia?
Caused by: java.lang.IllegalStateException: InputStream has already been read - do not use InputStreamResource if a stream needs to be read multiple times
at org.springframework.core.io.InputStreamResource.getInputStream(InputStreamResource.java:97) ~[task/:na]
at org.springframework.batch.item.file.DefaultBufferedReaderFactory.create(DefaultBufferedReaderFactory.java:34) ~[task/:na]
at org.springframework.batch.item.file.FlatFileItemReader.doOpen(FlatFileItemReader.java:266) ~[task/:na]
at org.springframework.batch.item.support.AbstractItemCountingItemStreamItemReader.open(AbstractItemCountingItemStreamItemReader.java:146) ~[task/:na]
Class to read from s3 bucket
@Service
public class S3BucketProcessing {
private static final AmazonS3 s3 = AmazonS3ClientBuilder.standard().build();
public InputStreamResource readFile() throws IOException{
String bucketName = "mybuckey";
String key = "File.txt";
S3Object object = s3.getObject(new GetObjectRequest(bucketName, key));
return new InputStreamResource(object.getObjectContent());
}
Primavera clase lector lote
@Component
public class MyReader extends FlatFileItemReader<MyEntity> {
MyLineMapper mapper;
MyTokenizer tokenizer;
S3BucketProcessing s3BucketProcessing;
@Autowired
public MyReader(MyTokenizer tokenizer, MyLineMapper mapper, S3BucketProcessing s3BucketProcessing) throws Exception{
LOG.info("CardCustomerNotificationReader constructor");
this.mapper = mapper;
this.tokenizer = tokenizer;
this.s3BucketProcessing= s3BucketProcessing;
this.setResource(s3BucketProcessing.readFile());
mapper.setLineTokenizer(tokenizer);
this.setLineMapper(mapper);
}
}
Teddy:
Los documentos sugieren el uso de ByteArrayResource para almacenar en caché el contenido en la memoria, en lugar de InputStreamResource.
Sólo cambia la parte vuelve de esta manera:
//As suggested by berzerk
byte[] content = IOUtils.toByteArray(object.getObjectContent());
//Then
return new ByteArrayResource( content );