What kind of concurrent Java atom? how to use?

  • JDK Atomic beginning of the class is to solve the problem of concurrency, atomicity principle by CAS
  • 3 parameters CAS, CAS (V, E, N). V represents a variable to be updated, E represents the expected value of the current variable, N denotes the updated value. Only when the value of the variable V is equal to E, the value will be updated variable V is N. If the variable is not equal to the value of V E, explained the value of the variable V has been updated, the current thread does nothing and returns the update failure
  • When multiple threads simultaneously using CAS update a variable, only one thread can update is successful, other have failed. The failure of the thread is not suspended, it can continue to retry CAS, you can also abort the operation
  • Atomic CAS operation is ensured by the CPU to complete a single instruction. Unsafe by the JDK API class completed
  • In the case of high concurrency, there will be a large number of CAS and retry the update fails, it is necessary to caution
  • java.util.concurrent.atomic package into atoms: atoms of the basic data types of the object reference type atom, an array of atoms, atomic object attributes and updating atomic accumulator
原子性基本数据类型:AtomicBoolean、AtomicInteger、AtomicLong
原子性对象引用类型:AtomicReference、AtomicStampedReference、AtomicMarkableReference
原子性数组:AtomicIntegerArray、AtomicLongArray、AtomicReferenceArray
原子性对象属性更新:AtomicIntegerFieldUpdater、AtomicLongFieldUpdater、AtomicReferenceFieldUpdater
原子性累加器:DoubleAccumulator、DoubleAdder、LongAccumulator、LongAdder

 

Unused atoms class, test code

package constxiong.interview;
 
/**
 * JDK 原子类测试
 * @author ConstXiong
 */
public class TestAtomic {
 
	private int count = 0;
	
	public int getAndIncrement() {
		return count++;
	}
	
//	private AtomicInteger count = new AtomicInteger(0);
//	
//	public int getAndIncrement() {
//		return count.getAndIncrement();
//	}
	
	public static void main(String[] args) {
		final TestAtomic test = new TestAtomic();
		for (int i = 0; i <3; i++) {
			new Thread(){
				@Override
				public void run() {
					for (int j = 0; j <10; j++) {
						try {
							Thread.sleep(100);
						} catch (InterruptedException e) {
							e.printStackTrace();
						}
						System.out.println(Thread.currentThread().getName() + " 获取递增值:" + test.getAndIncrement());
					}
				}
			}.start();
		}
	}
	
	
}

 

Print results, contain duplicate values

Thread-0 获取递增值:1
Thread-2 获取递增值:2
Thread-1 获取递增值:0
Thread-0 获取递增值:3
Thread-2 获取递增值:3
Thread-1 获取递增值:3
Thread-2 获取递增值:4
Thread-0 获取递增值:5
Thread-1 获取递增值:5
Thread-1 获取递增值:6
Thread-2 获取递增值:8
Thread-0 获取递增值:7
Thread-1 获取递增值:9
Thread-0 获取递增值:10
Thread-2 获取递增值:10
Thread-0 获取递增值:11
Thread-2 获取递增值:13
Thread-1 获取递增值:12
Thread-1 获取递增值:14
Thread-0 获取递增值:14
Thread-2 获取递增值:14
Thread-1 获取递增值:15
Thread-2 获取递增值:15
Thread-0 获取递增值:16
Thread-1 获取递增值:17
Thread-0 获取递增值:19
Thread-2 获取递增值:18
Thread-0 获取递增值:20
Thread-1 获取递增值:21
Thread-2 获取递增值:22

 

Test code type modify atoms

package constxiong.interview;
 
import java.util.concurrent.atomic.AtomicInteger;
 
/**
 * JDK 原子类测试
 * @author ConstXiong
 * @date 2019-06-11 11:22:01
 */
public class TestAtomic {
 
//	private int count = 0;
//	
//	public int getAndIncrement() {
//		return count++;
//	}
	
	private AtomicInteger count = new AtomicInteger(0);
	
	public int getAndIncrement() {
		return count.getAndIncrement();
	}
	
	public static void main(String[] args) {
		final TestAtomic test = new TestAtomic();
		for (int i = 0; i <3; i++) {
			new Thread(){
				@Override
				public void run() {
					for (int j = 0; j <10; j++) {
						try {
							Thread.sleep(100);
						} catch (InterruptedException e) {
							e.printStackTrace();
						}
						System.out.println(Thread.currentThread().getName() + " 获取递增值:" + test.getAndIncrement());
					}
				}
			}.start();
		}
	}
	
	
}

The printed result, does not contain duplicate values

Thread-0 获取递增值:1
Thread-2 获取递增值:2
Thread-1 获取递增值:0
Thread-0 获取递增值:3
Thread-1 获取递增值:4
Thread-2 获取递增值:5
Thread-0 获取递增值:6
Thread-1 获取递增值:7
Thread-2 获取递增值:8
Thread-0 获取递增值:9
Thread-2 获取递增值:10
Thread-1 获取递增值:11
Thread-0 获取递增值:12
Thread-1 获取递增值:13
Thread-2 获取递增值:14
Thread-0 获取递增值:15
Thread-1 获取递增值:16
Thread-2 获取递增值:17
Thread-0 获取递增值:18
Thread-1 获取递增值:19
Thread-2 获取递增值:20
Thread-0 获取递增值:21
Thread-2 获取递增值:23
Thread-1 获取递增值:22
Thread-0 获取递增值:24
Thread-1 获取递增值:25
Thread-2 获取递增值:26
Thread-0 获取递增值:27
Thread-2 获取递增值:28
Thread-1 获取递增值:29


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Origin www.cnblogs.com/ConstXiong/p/12118076.html