Twelve operating difficulties (there are large cattle passing IT can help me answer my questions are extremely grateful?) - the bitter pressing switch

Blog writing style began to change today, not much else to say.

Today topics are as follows:

# 7, the write function, performs the following functions: (8 points) 
# example: 
# user_list = [ 
#      { "name": "Alex", "Hobby": "Smoke"}, 
#      { "name": "Alex" , "hobby": "drink"} 
#      { "name": "Alex", "hobby": "hot head"} 
#      { "name": "wusir", "hobby": "call wheat"}, 
#      { "name": "wusir", "Hobby": "hip-hop"}, 
#            ] 
# write function processes user_list and return the following results: 
# [{ "name": "Alex", "hobby_list": [ "smoke." , "drink", "hot head"]},
# {"name":"wuhir","hobby_list": ["喊麦"，"街舞"]},]

I would like to write their own writing process method, the first direct look at the complete correct code directly look down

Read the title beginning, I found that the law is "alex", "name", "hobby" became a by multiple

So I thought of using the set to re-set

I want to put a list of key user_list collected and turned into a list, then go through a re-set collection

But come the following code can no longer be found when the handwritten code, I think I know this idea is wrong with the

dict={}
list=[]
for a in user_list:
    # print(a)
    for k,v in a.items():
        # print(k,v)
        dict.setdefault(k,[]).append(v)
        for b,c in dict.items():
            print(b,c)
print(dict)

The above problem my card two or three hours I have been stuck in the 'name' and 'hobby' is set to a variable, leading to too many variables feel, can not start (quietly to force force: I do not know is not the reason)

If it is not the reason I said, I want to know where is the problem

So I can not think like a long time, and then go to Baidu to find, locate the following code, but I did not understand

= result []      # { 'name': 'Alex', 'hobby_list': [ 'smoke']} 
for User in user_list:
     # 1. empty list for loop, which determines whether the result of the presence of this person, if there is added hobby_list a Hobby.
     # 2. create a new dictionary does not exist. 
    for new_user in the Result:
         IF the User [ ' name ' ] == new_user [ ' name ' ]: 
            new_user [ ' hobby_list ' ] .append (the User [ ' Hobby ' ])
             BREAK 
    the else :
        December = {}
        dic["name"] = user['name']
        dic['hobby_list'] = [user['hobby']]
        result.append(dic)
print(result)

But I read it several times above code and retrial question several times, I think of a solution ideas

Ideas are as follows:

I have the results in a list, by the dictionary and found that, there is the name and hobby may be composed of a relatively key-value pair

Names and preferences may form another key-value pairs, so I thought of the name hobby into a dictionary, and then finally to become value

Specific code as follows:

def main(user_list):
    #有结果可知,我们需要字典和列表,所以先设dict和list
    dict={}
    list=[]
    for i in user_list:#这里通过for循环先把原列表中的字典提出来
        dict.setdefault(i['name'],[]).append(i['hobby'])#这里通过字典的setdefault的性质来把名字去重
    for k,v in dict.items():#这里通过for循环把上一步字典里的名字和爱好分开变成值
        list.append({'name':k,'hobby_list':v})#这里把名字和爱好变成的键变成字典里'name'和'hobby_list'的值
    return list
print(main(
[
    {"name": "alex","hobby":"抽烟"},
    {"name" :"alex","hobby":"喝酒"},
    {"name" :"alex","hobby":"烫头"},
    {"name":"wusir","hobby":"喊麦"},
    {"name":"wusir","hobby":"街舞"},
]
))

总结:写代码要看清要求是什么,不一定要顺着推,可以逆着推,有结果推出来,这样也或许可以解决问题