1 Introduction
The recent TV series "Light Me, Warm You" has become very popular. Everyone is working on the same love code for the male protagonist Arthur. However, although its source code is available online, it is not in C language and cannot be understood. I watched this video and roughly analyzed its operation process. To describe it in words, it is a lot of love, and it is displayed from the inside to the outside, from small to large.
2. Realize
My idea for writing this program is this. It's like putting an elephant in the refrigerator. Just open the refrigerator, put the elephant in, and close the refrigerator. The same goes for writing programs.
The first step is to calculate the coordinates, update the coordinates, and draw the love. This is a three-step process. Repeated calls can be achieved. The specific details inside can be viewed in the code.
3. Effect display
4. Compilation environment: VS2019+easyx graphics library plug-in
5. Code display:
#include<graphics.h>
#include<conio.h>
#include<time.h>
#include<math.h>
#include<sys/timeb.h>
struct MyLove
{
int NUMS; // 编号
double m;
double n;
double size;
bool Is_show;
int x;
int y;
};
MyLove mylove[400];
int CenterX = 320;
int CenterY = 180;
double Size = 60;
void initdata(); // 初始化数据
void updata(); // 更新
void movedata(); // 平移
void showdata(); // 显示
int* GetRand(int* buf, int count, int range); // 随机数的生成
void heart(int x0, int y0, int size, COLORREF C);
void HpSleep(int ms);
int main()
{
initgraph(640, 480);
initdata();
BeginBatchDraw();
while (true)
{
updata();
showdata();
HpSleep(30); // 改为精确延时
FlushBatchDraw();
cleardevice();
}
EndBatchDraw();
_getch();
return 0;
}
void updata()
{
int* buf = (int*)malloc(sizeof(int) * 20);
buf = GetRand(buf, 20, (int)(2 * Size / 0.01));
movedata();
for (int i = 0; i < 20; i++)
{
mylove[i].m = buf[i] * 0.01;
mylove[i].n = (((sin(buf[(int)i] * 0.01) * sqrt(fabs(cos(buf[(int)i] * 0.01)))) / (sin(buf[(int)i] * 0.01) + 1.4142)) - 2 * sin(buf[(int)i] * 0.01) + 2);
mylove[i].size = Size;
mylove[i].NUMS = i / 20;
mylove[i].Is_show = true;
mylove[i].x = (int)(-Size * mylove[i].n * cos(mylove[i].m) + CenterX);
mylove[i].y = (int)(-Size * mylove[i].n * sin(mylove[i].m) + CenterY - mylove[i].size);
}
for (int i = 20; i < 400; i++)
{
mylove[i].size = mylove[i].size + 1;
if (mylove[i].size > 80)
{
mylove[i].size = 80;
}
mylove[i].NUMS = i / 20;
mylove[i].x = (int)(-mylove[i].size * mylove[i].n * cos(mylove[i].m) + CenterX);
mylove[i].y = (int)(-mylove[i].size * mylove[i].n * sin(mylove[i].m) + CenterY - mylove[i].size);
}
}
void movedata()
{
for (int i = 399; i > 19; i--)
{
mylove[i] = mylove[i - 20];
}
}
void showdata()
{
settextcolor(RED);
wchar_t c = 0x59; // 0x28 是电话机在 Wingdings 字体中的对应编码
for (int i = 0; i < 400; i++)
{
settextstyle(mylove[i].NUMS + 10, 0, "Webdings");
setbkmode(TRANSPARENT);
outtextxy(mylove[i].x + 20, mylove[i].y + 20, c);
}
}
int* GetRand(int* buf, int count, int range)
{
struct timeb timeSeed;
ftime(&timeSeed);
srand(timeSeed.time * 1000 + timeSeed.millitm); // milli time
for (int i = 0; i < count; i++)
{
int randTmp = rand() % range;
for (int j = 0; j < i; j++)
{
if (buf[j] == randTmp)
{
break;//检查重复。
}
}
buf[i] = randTmp;
}
return buf;
}
void initdata()
{
for (int i = 0; i < 400; i++)
{
mylove[i].NUMS = 0;
mylove[i].m = 0;
mylove[i].n = 0;
mylove[i].size = 0;
mylove[i].Is_show = false;
mylove[i].x = 0;
mylove[i].y = 0;
}
}
// 精确延时函数(可以精确到 1ms，精度 ±1ms)
// by yangw80<[email protected]>, 2011-5-4
void HpSleep(int ms)
{
static clock_t oldclock = clock(); // 静态变量，记录上一次 tick
oldclock += ms * CLOCKS_PER_SEC / 1000; // 更新 tick
if (clock() > oldclock) // 如果已经超时，无需延时
oldclock = clock();
else
while (clock() < oldclock) // 延时
Sleep(1); // 释放 CPU 控制权，降低 CPU 占用率，精度 10~16ms
// Sleep(0); // 更高精度、更高 CPU 占用率，精度 1ms
}