林文烨 :
Why an actual number string read from a text can't be parsed with method Integer.valueOf()
in java?
Exception :
Exception in thread "main" java.lang.NumberFormatException: For input string: "11127"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:580)
at java.lang.Integer.valueOf(Integer.java:766)
at sharingBike.ReadTxt.readRecord(ReadTxt.java:91)
at sharingBike.ReadTxt.main(ReadTxt.java:17)
This is my code
File fileView = new File(filePath);
BufferedReader in = new BufferedReader(new InputStreamReader(new FileInputStream(fileView), "UTF-8"));
String line;
int count = 0;
while ((line = in.readLine()) != null) {
String[] lins = line.split(";");
int value;
value = Integer.valueOf(lins[0]);}
assylias :
Here is the content of your string:
System.out.println(Arrays.toString("11127".getBytes()));
which outputs:
[-17, -69, -65, 49, 49, 49, 50, 55]
The first three bytes are a UTF-8 BOM.
You can fix it by removing non-digits from the string first (and use parseInt
to return an int
instead of an Integer
):
int value = Integer.parseInt(lins[0].replaceAll("\\D", "");
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