How to generate random values where a percentage of them are 0?

ip696 :

I create a random stream

Random random = new Random();
Stream<Integer> boxed = random.ints(0, 100000000).boxed();

But I need 60% of the numbers generated to be 0, while the remaining can be truly random. How can I do it?

EDIT:

And I need only positive numbers and between 0-100

1
2
0
0
9
0
0
1
12

dasblinkenlight :

Since the size of the target interval is divisible by ten, you can count on the last digit of generated numbers being uniformly distributed. Hence, this simple approach should work:

• Generate numbers in the range 0..1000
• If the last digit of the random number r is 0..5, inclusive, return zero
• Otherwise, return r / 10

Here is this approach in code:

Stream<Integer> boxed = random.ints(0, 1000).map(r -> r%10 < 6 ? 0 : r/10).boxed();

Demo.

Guess you like

Origin http://10.200.1.11:23101/article/api/json?id=436864&siteId=1