How to terminate a thread that has been blocked for too long due to Socket.accept()?

Huy Đức Lê :

public class Slave implements Runnable {
   public ServerSocket slaveSocket;

   public Slave(ServerSocket sk) {socket = sk;}

   @Override
   public void run() {
      Socket client = slaveSocket.accept(); // slave will wait to serve a client
      // more code...

      Socket clientPart2 = slaveSocket.accept();
      // more code...
   }
}

public class Server {
   public static void main(String[] args) {
       // for example only, incomplete code
       ServerSocket serverSocket = new ServerSocket(0); // a client connect to 8088
       Slave slave = new Slave(serverSocket);
       new Thread(slave).start(); // slave serve the current client, the server wait for new client

       // send new slave's port to client ... 
   }
}

So I have a server that serves multiple clients at once. Whenever a client connects, the server will create a new Slave, send the IP/port of that slave to the client, then the client will work with the slave.

However, if the client receives the slave's address then do nothing (or quit) (Edit: it means the client and server are connected but the client do nothing, because for example the user goes for lunch) slaveSocket.accept() causes that slave Thread to run forever, which is wasteful.

I want the slave thread to exit after 30 second of waiting for slaveSocket.accept(). Since slaveSocket.accept() is blocking, I cannot do that from inside the void run().

What is the correct, clean way to solve this problem? Thank you.

Edit 1: a ServerSocket is passed to the slave because the client can have multiple processes that will connect to that slave. So it doesn't just perform one function.

Joni :

If you set a timeout with setSoTimeout and no client connects, ServerSocket.accept will throw an exception. You can catch this exception.

To set a timeout of 30 seconds, use:

serverSocket.setSoTimeout(30000)

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