I am new to Python and I am using Python 3.7. So, I am trying to make my dictionary value equal to set i.e., dictionaryNew[kId] = setItem. So basically I want each kId (key) to have a corresponding row of set as its value. I am using set because I don't want duplicate values in the row.
This is a piece from my code below:
setItem = set()
dictionaryNew = {}
for kId, kVals in dictionaryObj.items():
for index in kVals:
if (index is not None):
yourVal = 0
yourVal = yourVal + int(index[10])
setItem.add(str(yourVal))
print(setItem) #the output for this is correct
dictionaryNew[kId] = setItem
setItem.clear()
print(dictionaryNew)
When I print setItem, then the result is printed correctly.
Output of setItem:
{'658', '766', '483', '262', '365', '779', '608', '324', '810', '701', '208'}
But when I print dictionaryNew, the result is like the one displayed below.
Output of dictionaryNew:
{'12': set(), '13': set(), '17': set(), '15': set(), '18': set(), '10': set(), '11': set(), '14': set(), '16': set(), '19': set()}
I don't want the output to be like this. Instead, I want the dictionary to have a row of set with its values. But this is just printing empty set when I try to print dictionaryNew. So what should I do to solve this issue?
You're using the same setItem instance all along, if you remove setItem.clear() you'll see that every key points to the same value.
You may create a new set() at each iteration
dictionaryNew = {}
for kId, kVals in dictionaryObj.items():
setItem = set()
for index in kVals:
if index is not None:
setItem.add(str(int(index[10]))) # the temp sum with 0 is useless
dictionaryNew[kId] = setItem
Using dict-comprehension this it equivalent to
dictionaryNew = {
kId: {str(int(index[10])) for index in kVals if index is not None}
for kId, kVals in dictionaryObj.items()
}