How to take the first 3 random numbers from a 6 number loop?

ssethzz :

So I'm supposed to make an overloaded program in Java. I have made my 2 methods on averaging the 6 numbers and the first 3 numbers. But I don't know how to store it into the parameters for the two methods. Here's my code so far:

    Random number = new Random();
    Scanner input = new Scanner(System.in);

    int num;
    int sum = 0;

    for(int counter = 1; counter <=6; counter++){
        num = 1 + number.nextInt(20);
        System.out.printf("Random number #%s: %s%n",counter,num);
        }

    }
    public static int avg (int a, int b, int c, int d, int e, int f){
        return ((a+b+c+d+e+f)/6);
    }
    public static int avg (int a, int b, int c){
        return((a+b+c)/3);
    }

WJS :

I presume you aren't permitted to use arrays so just assign each to a variable.

        num1 = 1 + number.nextInt(20);
        num2 = 1 + number.nextInt(20);
        num3 = 1 + number.nextInt(20);
        // and so on for six numbers.

Then

       int avgerage = avg(num1, num2, num3, ...);

Note that since you are not using doubles your average won't have a decimal.

Otherwise, place the numbers in an array.

You can also do it like this:

      public int avg(int[] array) {
            int sum = 0;
            for (int i = 0; i < array.length; i++) {
              sum += array[i];
            }
            return sum/array.length;
       }

If permitted, I would recommend changing your values from int to double

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