How to understand the IP address block 222.125.80.128/26?

What is the number of available hosts contained in the IP address block 222.125.80.128/26, what is the smallest address, and what is the largest address?

IP /26 is the format of CIDR , the full name is classless inter domain route, which is called classless inter domain route, that is to say , the first 26 bits of the 32-bit IP are the network number, and all the latter can be assigned to the host:

222.125.80.128------------1101 1110.0111 1101.0101 0000.10 (00 0000) In
parentheses are the host bits, a total of six bits. 2^6=64
Then remove 222.125.80.128, the host address with all zero bits, and 222.125.80.191, the broadcast address , and there are
64-2=62 host addresses left.
The minimum address host bit 00 0001 is 222.125.80.129 The
maximum address host bit 11 1110 is 222.125.80.190




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