MoHammaD ReZa DehGhani :
This is my function who run a code every 2.5 seconds and check if a value seted to the true my progress will gone and ...
mHandler = new Handler();
continue_or_stop = true;
new Thread(new Runnable() {
@Override
public void run() {
// TODO Auto-generated method stub
while (continue_or_stop) {
try {
Thread.sleep(2500); // every 2.5 seconds
mHandler.post(new Runnable() {
@Override
public void run() {
// TODO Auto-generated method stub
if (sp.getFromPreferences("state_update").equals("true")) {
progress_main.setVisibility(View.GONE);
layout_main.setVisibility(View.VISIBLE);
btn_save_send.setVisibility(View.GONE);
getOutputs();
MDToast.makeText(getActivity(), "وضعیت دستگاه با موفقیت بروزرسانی شد", Toast.LENGTH_LONG, MDToast.TYPE_SUCCESS).show();
sp.saveToPreferences("state_update", "false");
Intent intent = new Intent(getContext(), MainActivity.class);
startActivity(intent);
}
// you can set continue_or_stop to false, for stop
}
});
} catch (Exception e) {
// TODO: handle exception
}
}
}
}).start();
now i want a time out for this method if the value not seted to true after a (for example 12 seconds) progress should gone and Toast it to user that something goes wrong and try again
frogatto :
You can check for the timeout based on the number of trials. Also using thread and Thread.sleep
for running a periodic task is not a good practice.
To run a periodic task, you can post a Runnable
to a Handler
with some delay using postDelayed
method.
private Handler mHandler = new Handler();
private int mTrials = 0;
private Runnable mPeriodicTask = new Runnable() {
public void run() {
// Do the check
mTrials += 1;
if (mTrials == /* timeout number */) {
// timeout
} else {
mHandler.postDelayed(this, 2500);
}
}
}
To run the task:
mHandler.postDelayed(mPeriodicTask, 2500);