Gamoxion :
On Codility there's this problem of counting the minimal number of jumps a frog has to make to reach Y position.
The problem reads as follow:
A small frog wants to get to the other side of the road. The frog is currently located at position X and wants to get to a position greater than or equal to Y. The small frog always jumps a fixed distance, D.
Count the minimal number of jumps that the small frog must perform to reach its target.
given three integers X, Y and D, returns the minimal number of jumps from position X to a position equal to or greater than Y.
For example, given:
X = 10
Y = 85
D = 30
the function should return 3, because the frog will be positioned as follows:
after the first jump, at position 10 + 30 = 40
after the second jump, at position 10 + 30 + 30 = 70
after the third jump, at position 10 + 30 + 30 + 30 = 100
I have "solved" the problem and gotten "3" as result, just like in the example. However when I submit my code, I only get 11% and fail every test aside from the example.
This is my code
int count = 0;
while(X <= Y){
X += D;
count++;
}
return count;
On my code I basically count the jumps needed to reach Y, which is the position the frog wants to get to. I'm not properly understanding the problem? If so, what I am missing?
Nico Schertler :
You are using the condition
while(X <= Y)
to make a new jump. However, in the case where X == Y, you have already reached your goal and don't want to jump further. Hence, update to
while(X < Y) //as long as we have not reached the goal