How many String objects would be created when concatenating multiple Strings?

bhpsh :

I was asked in an interview about the number of objects that will be created on the given problem:

String str1 = "First";
String str2 = "Second";
String str3 = "Third";
String str4 = str1 + str2 + str3;

I answered that there would be 6 objects created in the string pool.

3 would be for each of the three variables.
1 would be for str1 + str2 (let's say str).
1 would be for str2 + str3.
1 would be for the str + str3 (str = str1 + str2).

Is the answer I gave correct? If not, what is the correct answer?

Andrew Tobilko :

Any answer to your question will depend on the JVM implementation and the Java version currently being used. I think it's an unreasonable question to ask in an interview.

Java 8

On my machine, with Java 1.8.0_201, your snippet results in this bytecode

L0
 LINENUMBER 13 L0
 LDC "First"
 ASTORE 1
L1
 LINENUMBER 14 L1
 LDC "Second"
 ASTORE 2
L2
 LINENUMBER 15 L2
 LDC "Third"
 ASTORE 3
L3
 LINENUMBER 16 L3
 NEW java/lang/StringBuilder
 DUP
 INVOKESPECIAL java/lang/StringBuilder.<init> ()V
 ALOAD 1
 INVOKEVIRTUAL java/lang/StringBuilder.append (Ljava/lang/String;)Ljava/lang/StringBuilder;
 ALOAD 2
 INVOKEVIRTUAL java/lang/StringBuilder.append (Ljava/lang/String;)Ljava/lang/StringBuilder;
 ALOAD 3
 INVOKEVIRTUAL java/lang/StringBuilder.append (Ljava/lang/String;)Ljava/lang/StringBuilder;
 INVOKEVIRTUAL java/lang/StringBuilder.toString ()Ljava/lang/String;
 ASTORE 4

which proves that 5 objects are being created (3 String literals*, 1 StringBuilder, 1 dynamically produced String instance by StringBuilder#toString).

Java 12

On my machine, with Java 12.0.2, the bytecode is

// identical to the bytecode above
L3
 LINENUMBER 16 L3
 ALOAD 1
 ALOAD 2
 ALOAD 3
 INVOKEDYNAMIC makeConcatWithConstants(Ljava/lang/String;Ljava/lang/String;Ljava/lang/String;)Ljava/lang/String; [
  // handle kind 0x6 : INVOKESTATIC
  java/lang/invoke/StringConcatFactory.makeConcatWithConstants(Ljava/lang/invoke/MethodHandles$Lookup;Ljava/lang/String;Ljava/lang/invoke/MethodType;Ljava/lang/String;[Ljava/lang/Object;)Ljava/lang/invoke/CallSite;
  // arguments:
  "\u0001\u0001\u0001"
 ]
 ASTORE 4

which magically changes "the correct answer" to 4 objects since there is no intermediate StringBuilder involved.


*Let's dig a bit deeper.

12.5. Creation of New Class Instances

A new class instance may be implicitly created in the following situations:

  • Loading of a class or interface that contains a string literal (§3.10.5) may create a new String object to represent the literal. (This will not occur if a string denoting the same sequence of Unicode code points has previously been interned.)

In other words, when you start an application, there are already objects in the String pool. You barely know what they are and where they come from (unless you scan all loaded classes for all literals they contain).

The java.lang.String class will be undoubtedly loaded as an essential JVM class, meaning all its literals will be created and placed into the pool.

Let's take a randomly selected snippet from the source code of String, pick a couple of literals from it, put a breakpoint at the very beginning of our programme, and examine if the pool contains these literals.

public final class String
    implements java.io.Serializable, Comparable<String>, CharSequence,
               Constable, ConstantDesc {
    ...
    public String repeat(int count) {
        // ... 
        if (Integer.MAX_VALUE / count < len) {
            throw new OutOfMemoryError("Repeating " + len + " bytes String " + count +
                    " times will produce a String exceeding maximum size.");
        }
    }
    ...
}

They are there indeed.

As an interesting find, this IDEA's filtering has a side effect: the substrings I was looking for have been added to the pool as well. The pool size increased by one ("bytes String" was added) after I applied this.contains("bytes String").

Where does this leave us?

We have no idea whether "First" was created and interned before we call String str1 = "First";, so we can't state firmly that the line creates a new instance.

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