i have string like "10.000" i just want 10 as integer how to do it in java?

Amit :

I have a string like "10.000" I just want 10 as integer how to do it in java?

I have done`

public static final Comparator<Product> By_PRICE  = new Comparator<Product>() {
       @Override
       public int compare(Product o1, Product o2) {
           //for name
//           return o1.getName().compareTo(o2.getName());

//           return o1.getFinalPrice().compareTo(o2.getFinalPrice());


           return Integer.parseInt(o1.getFinalPrice()) > Integer.parseInt(o1.getFinalPrice()) ? -1
                   : (Integer.parseInt(o1.getFinalPrice()) < Integer.parseInt(o1.getFinalPrice())) ? 1 : 0;




//           if (o1.getFinalPrice().compareTo(o2.getFinalPrice())>0){
//               return 1;
//           }
//           else if (o1.getFinalPrice().compareTo(o2.getFinalPrice())<0){
//               return -1;
//           }
//           else {
//               return 0;
//           }

       }
   };

` like this i want to use it for my recyclerview if I switch on it will sort my data which am getting from JSON as a string i tried almost everything but cannot find the answer i want to sort it if switch on then ascending and if switch off then descending order

shanbhagsv :

As per https://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#round(float) use Math.round()

System.out.println(Math.round(Float.valueOf("10.000")))

i have string like "10.000" i just want 10 as integer how to do it in java?

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