georg :
I have got a map of objects:
Map<String, Transaction> _userIncome = {
'four': Transaction(amount: 450, date: DateTime.now(), title: 'Einkommen', accountType: 'timr', notes: 'joa' , icon: Icon(Icons.today,), id: 'kololdcd', repeat: 'always'),
'five': Transaction(amount: 60, date: DateTime.now(), title: 'Bruder', accountType: 'timr', notes: 'brother' , icon: Icon(Icons.today,), id: 'kolkfrcd', repeat: 'never'),
'six': Transaction(amount: 60, date: DateTime.now(), title: 'Rückerstattung', accountType: 'timr', notes: 'brother' , icon: Icon(Icons.today,), id: 'kolofkfrcd', repeat: 'never'),
};
And I would like to get the key if I know the values (the values are unique), so that I can delete the the entry by its key:
_userIncome.remove(key);
I can identify the entry with the given values:
_userIncome.values
.where((t) => t.date.difference(datte).inDays == 0 && t.id == transactionId);
But I have no clue how I get the matching key, so that I can delete the entry. Or is there a way to the delete an entry by its values?
I would love to hear some advice :)
Harsh Bhikadia :
Simply use removeWhere
to delete the entry directly. Following is the example:
_userIncome.removeWhere((k,t) => t.date.difference(datte).inDays == 0 && t.id == transactionId);
For getting the index(or rather entry), do something as following:
final key = _userIncome.entries
.firstWhere(
(entry) => entry.date.difference(datte).inDays == 0 && entry.id == transactionId,
orElse: () => null,
)
?.key;