The number of bits in a frame of 1920*1080 = 1920*1080 bits = 1920*1080/8 byte = 259 200 B = 1920*1080/8/1024 KB = 253.125 KB
High-definition TV programs are shot at the standard of 24 frames per second, but the refresh rate of the TV is 60HZ, which means that the TV screen is refreshed 60 times per second.
To play 24 frames per second on a display device that refreshes 60 times per second, you must fill in, or recreate the picture to meet the 60 refreshes per second.
The specific method is to change the first frame of the movie screen into two screens, the second frame into three screens, the third frame into two screens, and the fourth frame into three screens. This kind of technical term divided into 2~3 frames is called field frequency.
The meaning seems to mean that the original signal must first be interlaced by the player (24-frame picture becomes 60 fields), and then the signal is sent to the TV, and the TV will de-interlace them and display them in 1080p quality.
The relationship between bandwidth and network speed
The so-called 1M broadband actually refers to 1Mbps (megabits per second), that is, 1 x 1024/8 = 128KB/sec, but this is only a theoretical speed. In fact, about 12% of the information header identification is deducted. This kind of control signal, so the upper limit of its transmission speed should be about 112KB/sec.
According to the theoretical speed, to stably play 1920*1080 HD TV programs, the bandwidth required:
Bandwidth = 253.125 * 24/128 = 47.4609375 M
Calculated based on 12% control signal loss:
Bandwidth = 253.125 * 24/112 = 54.241071428571 M
So in fact, under the premise of stable broadband speed, 60M broadband is generally required to watch 1920*1080 (24 frames/sec standard shooting) TV programs.
In the same way, 2k 4k 8k and other resolutions can be obtained.