Fu Ge's answer 2020-09-26: #福大Architects Daily One Question#
Variable definition: C++ is an alias. Rust is a pointer.
Take address and bitwise AND, C++ and rust are the same.
The c++ test code is as follows:
#include <iostream>
struct Point {
int x;
int y;
};
int main()
{
Point p1 = {
25,25 };
printf("p1.x address:%d\r\n", &p1.x);
printf("p1 address:%d\r\n", &p1);
Point& p2 = p1;
printf("p2.x address:%d\r\n", &p2.x);
printf("p2 address:%d\r\n", &p2);
printf("p1和p2地址相同,说明p2起到了别名的作用。p2.x和p2地址相同,说明p2保存的是内容,而不是地址。\r\n");
std::system("pause");
return 0;
}
The running results are as follows: The
rust test code is as follows:
struct Point {
x: i64,
y: i64,
}
fn main() {
let p1 = Point {
x: 25, y: 25 };
println!("p1.x address: {:p}", &p1.x);
println!("p1 address: {:p}", &p1);
let p2: &Point = &p1;
println!("p2.x address: {:p}", &p2.x);
println!("p2 address: {:p}", &p2);
println!("p1和p2地址不同,说明p2不是p1的别名。p2.x和p2地址不同,说明p2是指针。");
}
The results are as follows: