FastJson的坑

1.list中放入同一个对象,会出现内存地址引用{"$ref":"#[0]"},后台可以识别,但是前台不会识别

@Test
    public void testList(){
        
        User user = new User();
        user.setUserName("cgx");
        user.setPassword("123456");
        
        User user1 = new User();
        user1.setUserName("zbz");
        user1.setPassword("123456");
        
        ArrayList list = new ArrayList();
        list.add(user);
        list.add(user1);
        list.add(user);
        
        String jsonString = JSON.toJSONString(list,SerializerFeature.DisableCircularReferenceDetect);//关闭循环引用
        System.out.println(jsonString);
    }
JSON.toJSONString(list,true),会格式化json,方便查看

2.对象相互包含

@Test
    public void testList1(){
        
        User user = new User();
        user.setUserName("cgx");
        user.setPassword("123456");
        
        
        HashSet<Role> roles = new HashSet<Role>();
        HashSet<User> users = new HashSet<User>();
        users.add(user);
        
        
        Role role = new Role();
        role.setName("测试角色");
        role.setUsers(users);
        roles.add(role);
        
        user.setRoles(roles);
        
        //两种办法防止循环引用
        //1.在bean的属性上直接@JSONField(serialize=false)去掉不需要转换的属性
        
        //2.
        
        // 遇到sid和sname属性正常进行转换json
        SimplePropertyPreFilter filter = new SimplePropertyPreFilter("password","roles","name");
        
        
        String jsonString = JSON.toJSONString(user,filter,SerializerFeature.DisableCircularReferenceDetect);
        System.out.println(jsonString);
    }

  在实体类中使用@JSONField(serialize=false),是不是此字段就不返回了,放弃转换该字段

  filter进行过滤,想要现实的字段,进行转换的字段,写在过滤中,其他不进行转换

 

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转载自www.cnblogs.com/soul-wonder/p/9080403.html