归并排序和快速排序模版

摘自Acwing

归并排序

 1 #include <iostream>
 2 using namespace std;
 3 
 4 const int N = 1e5 + 10;
 5 
 6 int n;
 7 int q[N], tmp[N];
 8 void merge_sort(int q[], int l, int r)
 9 {
10     if (l >= r)
11         return;
12     int mid = l + r >> 1;
13     merge_sort(q, l, mid), merge_sort(q, mid + 1, r); // recurse until 
14     
15     int k = 0, i = l, j = mid + 1;
16     while (i <= mid && j <= r) // two pointer
17     {
18         if (q[i] <= q[j])
19             tmp[k++] = q[i++];
20         else
21             tmp[k++] = q[j++];
22     }
23     while (i <= mid) // remaining of left part
24         tmp[k++] = q[i++];
25     while (j <= r)
26         tmp[k++] = q[j++]; // remaining of right part
27     for (i = l, j = 0; i <= r; i++, j++) // place them in the correct location
28         q[i] = tmp[j];
29 }
30 int main()
31 {
32     scanf("%d", &n);
33     for (int i = 0; i < n; ++i)
34         scanf("%d", &q[i]);
35     merge_sort(q, 0, n - 1);
36     for (int i = 0; i < n; ++i)
37         printf("%d ", q[i]);
38     return 0;
39 }

N:最大数组长度(+10防止溢出)

n: 数组长度

q:原未排序数组 -> 排好序数组

tmp: 当前分离的两部分通过双指针找到的排好序的数组(类似选择排序)

每次得到tmp之后要把它放到正确的q的位置,所以加了26 - 27行

快速排序

 1 #include <iostream>
 2 using namespace std;
 3 const int N = 1e5 + 10;
 4 
 5 int n;
 6 int q[N];
 7 
 8 void quick_sort(int q[], int l, int r)
 9 {
10     if (l >= r)
11         return;
12     int x = q[(l + r) / 2], i = l - 1, j = r + 1;
13     while (i < j)
14     {
15         while (q[++i] < x);
16         while (q[--j] > x);
17         if (i < j) swap(q[i], q[j]);
18     }
19     quick_sort(q, l, j);
20     quick_sort(q, j + 1, r);
21 }
22 
23 int main() 
24 {
25     scanf("%d", &n);
26     for (int i = 0; i < n; ++ i)
27         scanf("%d", &q[i]);
28     quick_sort(q, 0, n - 1);
29     for (int i = 0; i < n; ++ i)
30         printf("%d ", q[i]);
31     return 0;
32 }


N:最大数组长度(+10防止溢出)

n: 数组长度

q:原未排序数组 -> 排好序数组

x:partition point

i和j:最左和最右的指针(类似selection sort)

与merge sort不同的是先排序再递归,首先使用双指针把小于x的和大于x的放在x的左边和右边(一样的既在左边也可以在右边,所以算法不稳定)

partition的位置既可以是最左边,右边,中间,也可以是随机的,平均的是见复杂度是O(n)

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转载自www.cnblogs.com/goldenticket/p/12128458.html