猜年龄v2.0

'''
用户登录,只有三次机会

给定年龄，用户可以猜三次年龄

年龄猜对，让用户选择两次奖励,输入无效字符,让其选择要不要礼物

用户选择两次奖励后可以退出,选择第一次后提示还有一次
'''

基本信息定义

user_info_dict = {
'james':'007',
'thor':'001',
'ironman':'002',
'spiderman':'003'
}
prize_dict = {'0': 'durex', '1': 'okamoto', '2': 'Jissbon'}
login_count = 0
guess_count = 0
age = 30

用户名密码输入

while 1:
user_name = input("login the user'name:")
user_pwd = input("login the password:")
if login_count == 2:
print('error too many times.')
break

if (user_name in user_info_dict) and (user_info_dict.get(user_name) == user_pwd):
    print('start\n')
    break
else:
    login_count += 1
    print('name or password error')
    continue

while guess_count < 3:
# 输入数字才能加入猜数字
while 1:
guess_age = input('guess my age:'.strip().lstrip('0'))
if guess_age.isdigit():
break
else:
print('fucking number please!')

guess_age_int = int(guess_age)
guess_count += 1

# 核心判断
if guess_age_int > age:
    print('too old')
elif guess_age_int < age:
    print('too young')
else :
    print('bingo')
    print(prize_dict)
    prize_count = 0

    #选择奖励
    while prize_count < 2:
        prize_select = input('select a prize:')
        prize_count += 1
        if prize_select in prize_dict:
            print(f'you got a {prize_dict[prize_select]}')
        else:
            print('want to give up the prize?')
            choice = input('yes or no:')
            if choice == 'no':
                prize_count = 0
                continue
            else:
                break
        print('one more prize')
    break