SQL 上升的温度

给定一个 Weather 表,编写一个 SQL 查询,来查找与之前(昨天的)日期相比温度更高的所有日期的 Id。

+---------+------------------+------------------+
| Id(INT) | RecordDate(DATE) | Temperature(INT) |
+---------+------------------+------------------+
|       1 |       2015-01-01 |               10 |
|       2 |       2015-01-02 |               25 |
|       3 |       2015-01-03 |               20 |
|       4 |       2015-01-04 |               30 |
+---------+------------------+------------------+

例如,根据上述给定的 Weather 表格,返回如下 Id:

+----+
| Id |
+----+
|  2 |
|  4 |
+----+

Solution Code

# Write your MySQL query statement below
# 内联接和日期函数的使用

select w1.id Id from weather w1 
join weather w2 
on DateDiff(w1.RecordDate, w2.RecordDate) = 1 
    and w1.Temperature > w2.Temperature;

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转载自www.cnblogs.com/sumelt/p/10548688.html
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