11.2森林冰火人

先把所有的雪人当成都是第一天做的,然后存在优先队列里面,然后从第一天开始算总共化了多少,如果超过当前最小的雪人,那么就把雪人化到0,弹出就好

#include<bits/stdc++.h>
#define sf scanf
#define scf(x) scanf("%lld",&x)
#define scff(x,y) scanf("%d%d",&x,&y)
#define scfff(x,y,z) scanf("%d%d%d",&x,&y,&z)
#define vi vector<int>
#define mp make_pair
#define pf printf
#define prf(x) printf("%lld\n",x)
#define mm(x,b) memset((x),(b),sizeof(x))
#define rep(i,a,n) for (ll i=a;i<n;i++)
#define per(i,a,n) for (ll i=a;i>=n;i--)
typedef long long ll;
using namespace std;
const ll mod=1e9+7;
const double eps=1e-6;
const double pi=acos(-1.0);
const int inf=0xfffffff;
const int N=1e5+7;
ll sum[N],a[N],tot[N];

struct node
{
    ll id;ll sum;
    node(ll a=0,ll b=0){id=a;sum=b;}
    friend bool operator <(node a,node b)
    {
        return a.sum >b.sum ;
    } 
};

priority_queue<node> v;
int main()
{
    node t;
    mm(sum,0); 
    ll n;scf(n);
    rep(i,1,n+1) scf(tot[i]);
    rep(i,1,n+1) scf(a[i]);
    ll qq=a[1];
    rep(i,2,n+1)
    {
        tot[i]+=qq;
        qq+=a[i];
    }
    rep(i,1,n+1)  v.push(node(i,tot[i]));
    ll sum1,num=0;
    ll now=0;
    rep(i,1,n+1)
    {
        now+=a[i];
        num++;
        sum1=num*a[i];
        while(!v.empty())
        {
            t=v.top();
            if(t.sum <now)
            {
                v.pop();
                num--;
                //sum1-=a[i];
                sum1+=t.sum -now;
            }else
            break;
        }
        if(n!=i)
            pf("%d ",sum1);
        else 
            prf(sum1);
    }
//  rep(i,1,n+1)    prf(tot[i]);
    return 0;
}

猜你喜欢

转载自www.cnblogs.com/wzl19981116/p/10087400.html
0条评论
添加一条新回复