c++大数重载模板

#include <bits/stdc++.h>
using namespace std;
const int MAXN=9999,MAXSIZE=1000,DLEN=4;
class BigNum
{
private:
    int a[MAXSIZE];    //可以控制大数的位数
    int len;       //大数长度
public:
    BigNum()
    {
        len = 1;    //构造函数
        memset(a,0,sizeof(a));
    }
    BigNum(const int);       //将一个int类型的变量转化为大数
    BigNum(const char*);     //将一个字符串类型的变量转化为大数
    BigNum(const BigNum &);  //拷贝构造函数
    BigNum &operator=(const BigNum &);   //重载赋值运算符,大数之间进行赋值运算
    friend istream& operator>>(istream&,  BigNum&);   //重载输入运算符
    friend ostream& operator<<(ostream&,  BigNum&);   //重载输出运算符
    BigNum operator+(const BigNum &) const;   //重载加法运算符,两个大数之间的相加运算
    BigNum operator-(const BigNum &) const;   //重载减法运算符,两个大数之间的相减运算
    BigNum operator*(const BigNum &) const;   //重载乘法运算符,两个大数之间的相乘运算
    BigNum operator/(const int   &) const;    //重载除法运算符,大数对一个整数进行相除运算
    BigNum operator^(const int  &) const;    //大数的n次方运算
    int    operator%(const int  &) const;    //大数对一个int类型的变量进行取模运算
    bool   operator>(const BigNum & T)const;   //大数和另一个大数的大小比较
    bool   operator==(const BigNum & T) const; //两个大数相等
    bool   operator>(const int & t)const;      //大数和一个int类型的变量的大小比较
    void print() //输出大数
    {
        printf("%d",a[len-1]);
        for(int i = len - 2 ; i >= 0 ; i--) printf("%04d",a[i]);
        printf("\n");
    }
};

BigNum::BigNum(const int b)     //将一个int类型的变量转化为大数
{
    int c,d = b;
    len = 0;
    memset(a,0,sizeof(a));
    while(d > MAXN)
    {
        c = d - (d / (MAXN + 1)) * (MAXN + 1);
        d = d / (MAXN + 1);
        a[len++] = c;
    }
    a[len++] = d;
}
BigNum::BigNum(const char*s)     //将一个字符串类型的变量转化为大数
{
    int t,k,index,l;
    memset(a,0,sizeof(a));
    l=strlen(s);
    len=l/DLEN;
    if(l%DLEN) len++;
    index=0;
    for(int i=l-1; i>=0; i-=DLEN)
    {
        t=0;
        k=i-DLEN+1;
        if(k<0) k=0;
        for(int j=k; j<=i; j++) t=t*10+s[j]-'0';
        a[index++]=t;
    }
}
BigNum::BigNum(const BigNum & T) : len(T.len)  //拷贝构造函数
{
    memset(a,0,sizeof(a));
    for(int i = 0 ; i < len ; i++) a[i] = T.a[i];
}
BigNum & BigNum::operator=(const BigNum & n)   //重载赋值运算符,大数之间进行赋值运算
{
    len = n.len;
    memset(a,0,sizeof(a));
    for(int i = 0 ; i < len ; i++) a[i] = n.a[i];
    return *this;
}

istream& operator>>(istream & in,  BigNum & b)   //重载输入运算符
{
    char ch[MAXSIZE*4];
    int i = -1,count=0,sum=0;
    in>>ch;
    for(i=strlen(ch)-1; i>=0;)
    {
        sum = 0;
        int t=1;
        for(int j=0; j<4&&i>=0; j++,i--,t*=10) sum+=(ch[i]-'0')*t;
        b.a[count]=sum;
        count++;
    }
    b.len =count++;
    return in;
}

ostream& operator<<(ostream& out,BigNum& b)  //重载输出运算符
{
    int i;
    cout<<b.a[b.len-1];
    for(i=b.len-2; i>=0; i--) printf("%04d",b.a[i]);
    return out;
}
BigNum BigNum::operator+(const BigNum & T) const   //两个大数之间的相加运算
{
    BigNum t(*this);
    int i,big;      //位数
    big = T.len > len ? T.len : len;
    for(i = 0 ; i < big ; i++)
    {
        t.a[i] +=T.a[i];
        if(t.a[i] > MAXN)
        {
            t.a[i + 1]++;
            t.a[i] -=MAXN+1;
        }
    }
    if(t.a[big] != 0) t.len = big + 1;
    else t.len = big;
    return t;
}

BigNum BigNum::operator-(const BigNum & T) const   //两个大数之间的相减运算
{
    int i,j,big;
    bool flag;
    BigNum t1,t2;
    if(*this>T)
    {
        t1=*this;
        t2=T;
        flag=0;
    }
    else
    {
        t1=T;
        t2=*this;
        flag=1;
    }
    big=t1.len;
    for(i = 0 ; i < big ; i++)
    {
        if(t1.a[i] < t2.a[i])
        {
            j = i + 1;
            while(t1.a[j] == 0)
                j++;
            t1.a[j--]--;
            while(j > i)
            {
                printf("%d",a[len-1]);
                for(int i = len - 2 ; i >= 0 ; i--)
                    printf("%04d",a[i]);
                printf("\n");
            }
            t1.a[j--] += MAXN;
            t1.a[i] += MAXN + 1 - t2.a[i];
        }
        else t1.a[i] -= t2.a[i];
    }
    t1.len = big;
    while(t1.a[len - 1] == 0 && t1.len > 1)
    {
        t1.len--;
        big--;
    }
    if(flag) t1.a[big-1]=0-t1.a[big-1];
    return t1;
}
BigNum BigNum::operator*(const BigNum & T) const   //两个大数之间的相乘运算
{
    BigNum ret;
    int i,j,up;
    int temp,temp1;
    for(i = 0 ; i < len ; i++)
    {
        up = 0;
        for(j = 0 ; j < T.len ; j++)
        {
            temp = a[i] * T.a[j] + ret.a[i + j] + up;
            if(temp > MAXN)
            {
                temp1 = temp - temp / (MAXN + 1) * (MAXN + 1);
                up = temp / (MAXN + 1);
                ret.a[i + j] = temp1;
            }
            else
            {
                up = 0;
                ret.a[i + j] = temp;
            }
        }
        if(up != 0) ret.a[i + j] = up;
    }
    ret.len = i + j;
    while(ret.a[ret.len - 1] == 0 && ret.len > 1) ret.len--;
    return ret;
}
BigNum BigNum::operator/(const int & b) const   //大数对一个整数进行相除运算
{
    BigNum ret;
    int i,down = 0;
    for(i = len - 1 ; i >= 0 ; i--)
    {
        ret.a[i] = (a[i] + down * (MAXN + 1)) / b;
        down = a[i] + down * (MAXN + 1) - ret.a[i] * b;
    }
    ret.len = len;
    while(ret.a[ret.len - 1] == 0 && ret.len > 1) ret.len--;
    return ret;
}

int BigNum::operator %(const int & b) const    //大数对一个int类型的变量进行取模运算
{
    int i,d=0;
    for (i = len-1; i>=0; i--) d = ((d * (MAXN+1))% b + a[i])% b;
    return d;
}


BigNum BigNum::operator^(const int &n)const  //大数的n次方运算
{
    BigNum t,ret(1);
    int i;
    if(n<0) exit(-1);
    if(n==0) return 1;
    if(n==1) return *this;
    int m=n;
    while(m>1)
    {
        t=*this;
        for(i=1; (i<<1)<=m; i<<=1) t=t*t;
        m-=i;
        ret=ret*t;
        if(m==1) ret=ret*(*this);
    }
    return ret;
}

bool BigNum::operator>(const BigNum & T) const   //大数和另一个大数的大小比较
{
    int ln;
    if(len > T.len) return true;
    else if(len == T.len)
    {
        ln = len - 1;
        while(a[ln] == T.a[ln] && ln >= 0) ln--;
        if(ln >= 0 && a[ln] > T.a[ln]) return true;
        else return false;
    }
    else return false;
}
bool BigNum::operator==(const BigNum & T) const   //大数和另一个大数的大小比较
{
    int ln;
    if(len != T.len) return false;
    else
    {
        for (int i=0; i<len; i++)
            if (a[i]!=T.a[i]) return false;
            else return true;
    }
}
bool BigNum::operator >(const int & t) const    //大数和一个int类型的变量的大小比较
{
    BigNum b(t);
    return *this>b;
}

int main()
{
    BigNum a,c;
    int b;
    cin>>a>>b;
    c=a%b;
    c.print();

    return 0 ;
}

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转载自blog.csdn.net/weixin_41058467/article/details/81324452