三种做法——判断给定的字符序列是否是回文,回文是指一个字符序列以中间字符为基础,两边字符忽略大小写完全相同

判断给定的字符序列是否是回文,回文是指一个字符序列以中间字符为基础,两边字符忽略大小写完全相同(10分)

判断回文多种方法:

不值得推荐方法:纯死脑筋做法

package jiCheng_duoTai;

import java.util.Scanner;

public class Test{
    
    
	public static void main(String[] args) {
    
    
		Scanner sc = new Scanner(System.in);
		System.out.print("请输入一行字符串:");
		String s = sc.next();
		boolean b = false;
		char []c =s.toCharArray();
		int i = c.length;
//		System.out.println(i);
		int k =i/2;
		if(i%2==0) {
    
    
			if(c[k]!=c[k-1])
				b = false;
			else {
    
    
				int t = i;
				for(int j=0;j<k-1;j++,t--) {
    
    
					if(c[j]==c[t-1])
						b = true;
					else {
    
    
						b = false;
						break;
					}
				}
			}
		}else {
    
    
			int t = i;
			for(int j=0;j<k;t--,j++) {
    
    
				if(c[j]==c[t-1])
					b = true;
				else {
    
    
					b = false;
					break;
				}
			}
		}
		if(b==false)
			System.out.println("不是回文");
		else
			System.out.println("是回文");
		
		sc.close();
	}
}

也不推荐做法,还是有点low

import java.util.Scanner;

public class Sum {
    
    
	public static void main(String[] args) {
    
    
		Scanner sc = new Scanner(System.in);
		String s = sc.next();
		char ch[] = s.toCharArray();
		int i,j;
		for(i=0,j=ch.length-1;i<=ch.length/2;i++,j--) {
    
    
			if(ch[i]!=ch[j]){
    
    
				System.out.println(s+"不是回文");
				break;
			}
		}
			if(i>ch.length/2)
		System.out.println(s+"是回文");
		sc.close();
	}
}

StringBuffer和String之间的转换来做:推荐哦

import java.util.Scanner;

public class Sum {
    
    
	public static void main(String[] args) {
    
    
		Scanner sc = new Scanner(System.in);
		String s = sc.next();
		StringBuffer sb = new StringBuffer(s);
		sb.reverse();
		String s2 = new String(sb);
		char ch[] = s.toCharArray();
		char hh[] = s2.toCharArray();
		int i;
		for(i=0;i<=ch.length/2;i++) {
    
    
			if(ch[i]!=hh[i]) {
    
    
				System.out.println(s+"不是回文");
				break;
			}
		}
		if(i>ch.length/2) {
    
    
			System.out.println(s+"是回文");
		}
	}
}

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转载自blog.csdn.net/qq_45696288/article/details/122160453