参考:https://www.cnblogs.com/apebro/p/12581417.html
#include<stdio.h>
#include<time>
printf("Time used = %.2f\n", (double)clock() / CLOCKS_PER_SEC);
printf输出的时间是以秒为单位;
常数CLOCKS_PER_SEC是和操作系统相关,不要直接使用clock()获取的运行时间返回值,应除以CLOCKS_PER_SEC;
#include <iostream>
#include<time.h>
int main(int argc, char** argv) {
for (int i = 0; i < 214748280; i++) {
i++;
}
for (int i = 0; i < 214748280; i++) {
i++;
}
// 输出运行时间;
std::cout << "The run time is: " <<(double)clock() / CLOCKS_PER_SEC << "s" << std::endl;
return 0;
}
如果是希望得到程序段运行的时间怎么办?
#include <iostream>
#include<time.h>
int main(int argc, char** argv) {
double startTime1 = clock();//1计时开始
for (int i = 0; i < 214748280; i++) {
i++;
}
double endTime1 = clock();//1计时结束
double startTime2 = clock();//2计时开始
for (int i = 0; i < 214748280; i++) {
i++;
}
double endTime2 = clock();//2计时结束
// 输出1运行时间;
std::cout << "The run time is: " <<(double)(endTime1 - startTime1) / CLOCKS_PER_SEC << "s" << std::endl;
// 输出2运行时间;
std::cout << "The run time is: " <<(double)(endTime2 - startTime2) / CLOCKS_PER_SEC << "s" << std::endl;
return 0;
}